**Could we have a google of
any items on our planet?**

Mass of Earth in grams = 5.9763 x 10^{27} grams.

^{23} grams/mole

^{23 }molecules of hydrogen will have a
weight of 1.0079 grams.

^{27} grams with 1.0079 grams per mole or
5.929457287 x 10^{27} moles of hydrogen.

^{23
}molecules, if we multiply :

(6.02252 x 10^{23 }molecules/mole)( 5.929457287 x 10^{27}
moles/earth)

^{(23 + 27)} molecules, or 35.7102751 x 10^{50}
molecules.

^{51}
molecules.

^{100} we are not even close.

^{100} molecules divided by 3.57102751 x 10^{51} molecules/earth = 0.280031446 x 10^{(100-51)} or 0.280031446 x 10^{49}
or in proper scientific notation, 2.80031446 x 10^{48} earths
made of hydrogen that would be needed to contain a google of hydrogen atoms.

^{48}
earths by 1837 we find we would only need 1.52439546 x 10^{45}
earth masses of electrons to have a google of electrons.

^{15}
earth weight objects side by side. Big
cube!

Looked at another way, since we think that an electron has
a diameter of about 1 x 10^{-12} cm, if we have a google of electrons piled up into a
cube we would need to have about 2.1544346900318837217592935665194 x 10^{33}
electrons in every direction. Since
each electron has a diameter of 1 x 10^{-12
}cm a row of electrons that long would be
2.1544346900318837217592935665194 x 10^{21 }cm which, since a centimeter is 1/100
of a meter, is

2.1544346900318837217592935665194 x 10^{19
}meters which, since a meter is 1/1000 of a kilometer, is

2.1544346900318837217592935665194 x 10^{16
}kilometers or 21544346900318837.217592935665194 kilometers, but,
since there are 1.609344 kilometers in a mile, is

13387036519425826.434617419063416 miles, but, since a light
year is 5.87851 x 10^{12}
miles, is

2277.2839579120944651990757969988 light years on a side.